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Mariana [72]
3 years ago
9

What Do You Think It Means To Have a Balanced Or Unbalanced Chemical Equation?

Chemistry
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.

Explanation:

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Which example best shows conservation of resources?
pashok25 [27]

Answer:

recycling aluminum cans and glass bottles

Explanation:

reusing is a good example of conservation of resources.

4 0
3 years ago
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If a sample of 0.500 moles of hydrogen sulfide (H2S) was reacted with excess concentrated sulfuric acid, how many moles of sulfu
ra1l [238]

Answer:

2.00

Explanation:

They said that was the answer.

6 0
3 years ago
What is 230 in scientific notation
Brums [2.3K]
The answer is 2.3x10^2.
6 0
3 years ago
How many moles of H2O are used to make 3.12 moles of NH3
mrs_skeptik [129]

Answer:

4.73 mol NH

Explanation:

What we're doing here is calculating basic mole-mole relationships, something that you'll be doing quite a bit!

The steps to solving mole-mole problems like this are

write the balanced chemical equation for the reaction (this is given)

divide the number of moles of the given known substance (3.55) by that substance's coefficient in the chemical equation (3)

multiply that number by the coefficient of the substance you're trying to find (4)

Using simple dimensional analysis, it looks like this:

6 0
3 years ago
Read 2 more answers
Given the following reaction: 2N2O5=2N2O4+O2, if the rate of oxygen production is 0.15M/min, determine:
astraxan [27]

Answer:

a. r_{N_2O_5}=-0.075M/min

b. r_{N_2O_4}=0.075M/min

Explanation:

Hello.

In this case, according to the balanced chemical reaction, we can write the law of rate proportions:

\frac{r_{N_2O_5}}{-2} =\frac{r_{N_2O_4}}{2} =\frac{r_{O_2}}{1}

Thus, we proceed as follows:

a. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_5}}{-2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_5}=\frac{r_{O_2}}{-2}  =\frac{0.15M/min}{-2}\\\\ r_{N_2O_5}=-0.075M/min

b. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_4}}{2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_4}=\frac{r_{O_2}}{2}  =\frac{0.15M/min}{2}\\\\ r_{N_2O_4}=0.075M/min

Best regards!

8 0
3 years ago
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