All categories

3 years ago

Why is it worthwhile to explore the moon again?

1 answer:

4 0

it might have lots of nickel gold and sliver that are all valuable to sustain the increase in tech.we can also live on the moon and can fit 1.46 trillion people

You might be interested in

Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is connected in series to a batt

BabaBlast [244]

Answer:

The maximum pressure is 10 V from across condenser.The highest charge mostly on condenser.
Vc = 10 x 1mf

= 10 ^ - 5C

The time it takes for the condenser to be 5 V different.
Thus we have, 0.69 x 10 ^ - 3 seconds.

5 0

2 years ago

Why is it necessary for cells to be so small

madreJ [45]

Answer:

Cells are small because they need to keep a surface area to volume ratio that allows for adequate intake of nutrients while being able to excrete the cells waste.

Explanation:

That is why the cell needs to be small

8 0

3 years ago

What is the current in a 160 V circuit if the resistance is 2

galben [10]

V= IR

160 = I × 2

80 A = I = current

8 0

3 years ago

Read 2 more answers

For total internal reflection to occur, all of the following must happen but __________. light must travel slower in the first m

bija089 [108]

Answer:

Explanation:

When a ray of light passes through denser medium to rarer medium and then after refraction it comes back into the denser medium, the phenomenon is called total internal refraction.

There are two necessary conditions for the total internal refraction.

(1) The refraction takes place g=from denser medium to rarer medium.

(2) The angle of incidence in the denser medium should be more than the critical angle for that pair of media.

6 0

4 years ago

Read 2 more answers

An infinitely long line of charge has linear charge density 6.00×10−12 C/m . A proton (mass 1.67×10−27 kg,charge +1.60×10−19 C)

Bogdan [553]

Answer:

$A) \,K.E=1.405\times 10^{-20}J$

$B)\,r_f=0.268\,m$

Explanation:

$Charge\,\,density=\lambda=6\times 10^{-12}C/n\\\\Mass\,\, of \,\,proton=m_p=1.67\times 10^{-27}kg\\\\charge\,\, of\,\, proton=q_p=1.609\times 10^{-19}C\\\\r=12\,cm=0.12\, m\\\\v=4.103\times 10^{3}m/s$

A) Initial kinetic energy of proton

$K.E=\frac{1}{2}m_pv^2\\\\K.E=1.405\times 10^{-20}J$

B) How close does the proton get to the line of charge?

Potential energy and kinetic energy are related as:

$K_i+U_i=K_f+U_f\\\\U_f-U_i=K_i-K_f\\\\q(V_f-V_i)=1.40\times 10^{-20}\\\\V_f-V_i=0.087--(1)\\$

Change in voltage is

$V_f-V_i=\frac{\lambda}{2\pi \epsilon_o}ln\frac{r_f}{r_i}\\\\ln|\frac{r_f}{r_i}|=(0.087)(\frac{2\pi \epsilon_o}{\lambda})\\\\ln|\frac{r_f}{r_i}|==0.8059\\\\\frac{r_f}{r_i}=2.24\\\\r_f=(2.24)(.12)\\\\r_f=0.268 m$

5 0

3 years ago