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3 years ago

10 POINTS! I NEED THIS QUESTION PLS! FIND THE AREA!!! THERE IS A SQUARE LEFT SIDE OF THE SQUARE IS 12 INCHES, WHATS THE AREA?

Mathematics

2 answers:

zubka84 [21]3 years ago

4 0

Answer:

144

Step-by-step explanation:

12x12=144

igor_vitrenko [27]3 years ago

4 0

Answer: 144 in

explanation: A= a^2 = 12^2 = 144
or
explanation: 12^2

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Please help i am so confused

harkovskaia [24]

Answer:

$q\geq -81$

Step-by-step explanation:

First, begin by multiplying $\frac{q}{27} \\$ by its reciprocal.

To do this, flip the fraction upside-down.

The resulting equation looks like this: $\frac{27}{1} *\frac{q}{27}$

Cancel out the two 27's and you are left with $\frac{q}{1}$ , which you can simplify to q.

Next, multiply -3 by $\frac{27}{1}$ . Remember, what you do on one side, you must do on the other.

Your equation should look like this:

$q\geq -81$

The final answer is $q\geq -81$ .

Have a nice day!

3 0

3 years ago

Write each mixed as a decimal. a) 1 3/4 b) 2 13/20

kakasveta [241]

Answer:

a. 1.75

b. 2.65

those are as a decimal

6 0

3 years ago

Solve 6 sin((π/5)x)=5 for the four smallest positive solutions

cupoosta [38]

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation $6\sin\left(\dfrac{\pi }{5}x\right)=5$ by 6:

$\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.$

Then

$\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,$

$x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.$

Since $\arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},$

four smallest positive solutions are

1. $\dfrac{5}{3.2}\approx 1.568,\ k=0;$

2. $\dfrac{-5}{3.2}+5\approx 3.432,\ k=1;$

3. $\dfrac{5}{3.2}+10\approx 11.568,\ k=2;$

4. $\dfrac{-5}{3.2}+15\approx 13.432,\ k=3.$

3 0

4 years ago

HELP ME PLEASE FOR BRAINLIEST!!!!

Brilliant_brown [7]

I think it is 10.

hope this helps!!! :D

3 0

3 years ago

Urgent. Please show all work

myrzilka [38]

Answer:

$\displaystyle f'(x) = \frac{4}{x^2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Differentiation

Derivatives
Derivative Notation

The definition of a derivative is the slope of the tangent line: $\displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle f(x) = -\frac{4}{x}$

Step 2: Differentiate

[Function] Substitute in x: $\displaystyle f(x + h) = -\frac{4}{x + h}$
Substitute in functions [Definition of a Derivative]: $\displaystyle f'(x) = \lim_{h \to 0} \frac{-\frac{4}{x + h} - \big( -\frac{4}{x} \big)}{h}$
Simplify: $\displaystyle f'(x) = \lim_{h \to 0} \frac{4}{x(x+ h)}$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle f'(x) = \frac{4}{x(x+ 0)}$
Simplify: $\displaystyle f'(x) = \frac{4}{x^2}$

∴ the derivative of the given function will be equal to 4 divided by x².

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Learn more about derivatives: brainly.com/question/25804880

Learn more about calculus: brainly.com/question/23558817

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0

2 years ago