Answer:
The answer to your question is T2 = 319.4°K
Explanation:
Data
Volume 1 = V1 = 852 ml
Temperature 1 = T1 = 288°K
Volume 2 = V2 = 945 ml
Temperature 2 = T2 = ?
Process
To solve this problem, use Charles' law.
V1/T1 = V2/T2
-Solve for T2
T2 = V2T1/V1
-Substitution
T2 = (945 x 288) / 852
-Simplification
T2 = 272160 / 852
-Result
T2 = 319.4°K
This means that neutral zinc atom has a total of 30 electrons surrounding its nucleus. To see how many of these electrons are valence electrons, write the electron configuration of a neutral zinc atom. Notice that the outermost shell, which for zinc is the fourth shell, n=4, has two electrons. Hope this helps. :)
Answer is: H₃PO₄.
A
phosphoric acid is three protic acid, which means that in water release tree
protons. Phosphoric acid ionizes in three steps in water.
<span>
First step: H</span>₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).<span>
Second step: H</span>₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).<span>
Third step: HPO</span>₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).<span>
Species that are present: H</span>₃PO₄,
H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺, but because the acid dissociation constants are low, very low percentage of acid dissociates.
I think it’s B
Sorry if I’m wrong
Answer:
A. 0.143 M
B. 0.0523 M
Explanation:
A.
Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).
KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄
The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:
1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol
The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.
5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:
M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M
B.
Let's consider the neutralization of potassium hydroxide and perchloric acid.
KOH + HClO₄ → KClO₄ + H₂O
When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.
