Question

C2d3 has a solubility product constant of 9.14×10−9. What is the molar solubility of c2d3?

Answer 1

Answer : The molar solubility of $C_2d_3$ is $9.67\times 10^{-3}M$

Explanation :

The solubility equilibrium reaction will be:

$C_2d_3\rightleftharpoons 2C^{3+}+3d^{2-}$

The expression for solubility constant for this reaction will be,

Let the molar solubility be, 'x'

$K_{sp}=(2x)^2\times (3x)^3$

Now put all the given values in this expression, we get:

$9.14\times 10^{-9}=108x^5$

$x=9.67\times 10^{-3}M$

Therefore, the molar solubility of $C_2d_3$ is $9.67\times 10^{-3}M$