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Alchen [17]
3 years ago
13

Which is the most prevalent species in a 0.25 m aqueous solution of phosphoric acid h3po4 g?

Chemistry
1 answer:
kap26 [50]3 years ago
8 0

Answer is: H₃PO₄.

A phosphoric acid is three protic acid, which means that in water release tree protons. Phosphoric acid ionizes in three steps in water.

<span> First step: H</span>₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).<span>
Second step: H</span>₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).<span>
Third step: HPO</span>₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).<span>
Species that are present: H</span>₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺, but because the acid dissociation constants are low, very low percentage of acid dissociates.

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Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.​
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<h3>Concept :</h3>

To boil water at 95°C, decrease the atmospheric pressure.

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The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
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The volume of carbon dioxide gas generated 468 mL.

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The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

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HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

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The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
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