The answer is
• AI +O2 = AI2O3 :)
Structure of a-chloro-b-methylbutyric acid (2-chloro-3-methylbutyric acid is attached below.
The structure was drawn using following information.
1) First, the parent chain was identified. The parent chain is containing four carbon atoms, also, this chain belongs to carboxylic acid as the compound name ends with Butyric acid i.e. butyr (Butane) -ic acid (carboxylic acid).
2) Secondly, the positions of substituents were assigned by using the rule which sates that the numbering in carboxylic acid must satrt from the carbonyl carbon. Therefore, the carbon which is attached to carbonyl carbon is named as alpha (2nd position) and carbon next to alpha carbon is named as beta carbon (3rd position). Hence, we add chlorine atom on 2nd carbon next to carbonyl group and methyl group at 3rd carbon with respect to carbonyl carbon.
Answer: Two chlorine atoms
Explanation:
Chlorine is a nonmetal belonging to group 7 of the periodic table. It has an atomic number of 17 distributed as (2, 8, 7), so it has 7 valence electrons and needs JUST ONE to complete its outermost shell.
Cl + e- ---> Cl-
On the other hand, barium is a metal belonging to group 2 on the periodic table. It has an atomic number of 56 with 2
valence electrons in its outermost shell, and gives off the two electrons to form a stable octet structure.
Ba ----> Ba2+ + 2e-
Thus, barium loses its 2 outermost electrons to form a Ba2+ ion, while TWO chlorine atoms receive them to form 2Cl- resulting in an ionic bond in the compound, BaCl2 (Barium Chloride)
Ba2+ + 2Cl- ---> BaCl2
Kp/Kc = RT
<h3>Further explanation</h3>
Given
Reaction
A(g) ⇌ C(g)+B(g)
Required
Kp/Kc
Solution
For reaction :
pA + qB ⇒ mC + nD
![\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKc%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
While the equilibrium constant Kp is based on the partial pressure
![\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKp%20~%20%3D%20~%20%5Cfrac%20%7B%5BpC%5D%20%5E%20m%20%5BpD%5D%20%5E%20n%7D%20%7B%5BpA%5D%20%5E%20p%20%5BpB%5D%20%5E%20q%7D%7D%7D%7D)
The value of Kp and Kc can be linked to the formula '

R = gas constant = 0.0821 L.atm / mol.K
Δn=moles products - moles reactants or
number of product coefficients-number of reactant coefficients
For reaction :
A(g) ⇌ C(g)+B(g)
number of product coefficients = 1+1=2
number of reactant coefficients = 1
Δn= 2 - 1 =1
So Kp/Kc = RT
Answer:
Alkenes are <u>Very Reactive</u>.
Explanation:
Other options are incorrect because;
Saturated compounds are those hydrocarbons which contains only single bonds, while alkenes contain atleast one double bond.
Single bonds again stands for saturated compounds, hence it is false.
Alkene are reactive because the double bond has the potential to open by addition reaction. So electrophiles are readily added across double bond. This reactivity can also be explained by the exposure of nucleophilic double bond above and below the plane, which is highly exposed to incoming electrophiles.