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Elanso [62]
3 years ago
13

¿Puede haber química y, por lo tanto puede haber vida en un mundo helado o demasiado caliente?

Chemistry
1 answer:
ioda3 years ago
8 0

Answer:

Yes and Yes

Explanation:

On earth, life has been discovered in very extreme places. The Mariana trench with its burgeoning pressure and temperature has a rich fauna life. Polar extremes with their skin deep freezing temperature also has signs of life. Hydrothermal vents are also known to house some of these extreme organisms. In fact, some form of life thrives and survives in very extreme cases.

If life can occur in these extreme conditions on earth, then with the right mix of biological matter, it will not be strange to find life in some very extreme planets.

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Explain how the ecosystem that you selected follows the law of conservation of mass and the law of conservation of energy. It is
trasher [3.6K]
In the ocean, light is used by phytoplankton in order to produce sugar.  10% of the energy from the sun is available to the zooplankton that eat the phytoplankton, the rest of the energy is lost as heat or through powering body building/functions/reproduction.  Whatever eats the zooplankton receives 10% of that energy in order to grow
3 0
4 years ago
Which claim about cats is most likely based on science?
MrRissso [65]

Answer:D

Explanation:

4 0
3 years ago
How do you think the human population has changed over time? What makes you say that?
kozerog [31]

Answer:The world population increased from 1 billion in 1800 to 7.7 billion today. The world population growth rate declined from 2.2% per year 50 years ago to 1.05% per year. Other relevant research: World population growth – This article is focusing on the history of population growth up to the present.

Explanation:

3 0
3 years ago
What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is K_2SO_3.

7 0
3 years ago
If 0.680 kg of copper(I) sulfide reacts with excess oxygen, what mass of copper metal may be produced ? A) 0.680 kg B) 0.136 kg
Katen [24]

Answer:

D. 0.543kg of copper metal is produced from 0.680kg of copper 1 sulphide.

Explanation:

First write the equation for the reaction:

Cu2S + O2 ------> 2Cu + SO2

Determine the mole ratio of the two substances:

I mole of Cu2O forms 2 moles of Copper metal

The number of moles of copper 1 sulphide used is;

n = mass of Cu2S / molar mass of Cu2S

Mass = 0.680kg = 680g

Molar mass = 159.16g/mol

n = 680g / 159.16g/mol

n = 4.272moles

Determine the number of mole of copper:

Number of moles of copper metal produced from 4.272moles of copper 1 sulphide is therefore:

n of copper = 2 * 4.272 Moles

n = 8.544moles.

Determine the mass copper:

The mass of copper metal produced is therefore = number of moles of copper * molar mass of copper

mass = 8.544 moles * 63.55g/mol

mass = 542.97grams

Mass = 0.543kg

5 0
4 years ago
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