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3 years ago

2. What is the accelaration of a 4000 kg airplane that has a force of 24,000 N?

Physics

1 answer:

Bond [772]3 years ago

8 0

Answer:

c) 6 m/s²

Explanation:

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What does amplitude mean

boyakko [2]

The maximum extent of a vibration, measured from the position of equilibrium.
The meaning of equilibrium is being in the position of physical balance.

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4 years ago

Arrange the stars based on their temperature. Begin with the coolest star, and end with the hottest star. Tiles yellow red blue

Oxana [17]

Red,yellow,white,and blue
Hope this helps!

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3 years ago

According to newton's second law of motion, when an object is acted on by an unbalanced force, how will that object respond?

Aneli [31]

D. It will accelerate

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3 years ago

Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s

Maru [420]

Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

$58 m/s - 9.8 m/s^2 *4.6 s = v0 = 12.92 m/s$

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

$y0 + v0*t + 1/2 g *t^2 = yt$

replacing

$0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m$

5 0

3 years ago

An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) Ho

PtichkaEL [24]

Answer:

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter = 299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density × g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 × 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 × 0.0304791 × 9.81

weigh is 2353.13 N

7 0

4 years ago