Total weight of the mixture of sand and salt = 5.25 g
Weight of sand separated = 3.64 g
Weight of the salt in the mixture = (5.25 - 3.64) g
= 1.61 g
Then the percentage of sand in the sample = [(3.64/5.25) * 100] percent
= 69.33%
So the percentage of sand in the total mixture of sand and salt is 69.33%.
Answer:
The molarity of the sulfuric acid is 0.018 M
Explanation:
The molarity of a solution is the number of moles of the solute (sulfuric acid in this case) in a 1-liter solution.
Every 100 g of the solution, we have 95 g sulfuric acid because its concentration is 95% w/w.
With the density, we can calculate how many liters are 100 g of solution:
density = mass / volume
1.85 g / ml = 100 g / volume
volume = 100 g / 1.85 g/ml
volume = 54.1 ml or 0.0541 l
Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:
1 l * 95g / 0.0541 l = 1.756 g sulfuric acid.
But we want to know how many moles sulfuric acid we have per liter. Then, using the molar mass, we can calculate how many moles there are in 1.756 g sulfuric acid:
1.756 g * 1 mol / 98.08 g = 0.018 mol
The molarity is 0.018 M
Answer: Ammonium, when heated with aqueous base, will give off NH3 (ammonia) gas, (and depending, water vapor). This will leave the Cr2O3(s). From then on,
it is just adding or subtraction of gases or water vapor. You probably heard “Loss of electrons is Oxidation”, “Gain of Electrons is reduction”. That should help.
Explanation: This isn’t an explanation but an interesting point; Acid-Base and RedOx reactions are useful to the most complex of any Chemistry. Get this down, and Organic Chemistry will be much easier.
Search up the answer on safari it will be easy
