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Alexeev081 [22]
3 years ago
8

Why does SO2 and water make H2SO3 and NOT H2SO4? Explain your answer.

Chemistry
1 answer:
Vlada [557]3 years ago
6 0
This is because the law of conservation of mass will not be followed if, from SO2 and water, sulfuric acid is formed. Making a balanced chemical reaction is not possible no matter what. To obtain sulfuric acid, SO2 still needs to be oxidized further to SO3.
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Help?… thank you very much! 100 points
Marianna [84]

Answer:

Option B is correct.

Explanation:

They live in less extreme environment than most archaebacteria.

Hoped this helped.

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2 years ago
What information is needed to determine the amount of moles in 1.6g of HCL?
alukav5142 [94]

Answer:

Molar mass and Mass

Explanation:

The relationship between mass and number of moles is given as;

Number of moles = Mass / Molar mass

Mass = 1.6 g

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Number of moles = 1.6 g / 36.5 g/mol

Number of moles = 0.0438 mol

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Which substance is most likely a lipid? -long chains of molecules composed of carbon, hydrogen, and oxygen atoms -compounds that
gulaghasi [49]

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The answer is

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3 years ago
Cuál es la presión atmosférica de tunja​
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7 0
3 years ago
If the equilibrium constant kc for the reaction below is 1.71 × 10–1, what will be the equilibrium pressure of no if the initial
NemiM [27]
The equilibrium reaction that is not shown is the reaction of N₂ and O₂ to form NO:

N₂ + O₂ ⇄ 2NO

We can write an expression for the equilibrium constant. We are given the value of Kc, but we must use Kp if we are dealing with partial pressures. However, since 2 moles of gas are formed from 2 moles of gas, the value of Kc is equal to Kp so we do not need to change anything.

Kc = (Pno)²/(Pn2)(Po2) = 1.71 x 10⁻¹

We must first use the initial pressures to find the reaction quotient to decide which way the equilibrium will shift:

Q = (1.96 x 10⁻³)²/(1.96 x 10⁻³)(1.96 x 10⁻³) = 1

Since Q > Kp, the equilibrium will shift to the left. Now we can prepare an ICE table to find the equilibrium pressures:

           N₂                       O₂                    NO
I      1.96 x 10⁻³       1.96 x 10⁻³         1.96 x 10⁻³
C       +x                         +x                    -2x
E    0.00196 + x     0.00196 + x        0.00196 - 2x

We enter these equilibrium pressures into the equilibrium expression and solve for x:

0.171 = (0.00196 - 2x)²/(0.00196 + x)²

Expand the equation and simplify to a quadratic function:

3.829x² - 0.00851x + 3.183·10⁻⁶ = 0

x = ((0.00851) +/- sqrt((0.00851)² - 4(3.829)(3.183 x 10⁻⁶)))/2(3.829)

x = 0.000476 atm

Now we can solve for the equilibrium partial pressures:

Pno = 0.00196 - 2(0.000476) = 0.00101 atm

Pn2 = 0.00196 + 0.000476 = 0.00244 atm

Po2 = 0.000196 + 0.000476 = 0.00244 atm

Therefore, the equilibrium partial pressure of NO is 0.00101 atm.
4 0
4 years ago
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