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snow_tiger [21]

2 years ago

11

Why are large crystals of sodium chloride used instead of small crystals when making ice cream

1 answer:

matrenka [14]2 years ago

6 0

Answer:

Sodium chloride is added to the ice to lower the freezing point of the ice. Large crystals dissolve more slowly than small crystals. This allows time for the ice cream to freeze more evenly.

Explanation:

You might be interested in

A. Choose one of the four biogeochemical cycles that were discussed in this unit - carbon, nitrogen, water, or oxygen and descri

MAVERICK [17]

Water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

<h3>What is are the stages of water cycle?</h3>

These are the basic stages through which water passes. These stages are:

Evaporation
Condensation
Precipitation
Collection.

So therefore, water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

Learn more about water cycle:

brainly.com/question/25796102

#SPJ1

6 0

2 years ago

What is the correct name for Na2CO3

KatRina [158]

Answer:

Sodium carbonate

Explanation:

6 0

3 years ago

Read 2 more answers

Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

3 years ago

The first excited vibrational energy level of diatomic chlo- rine (Cl2) is 558 cm^-1 above the ground state. Wave- numbers, the

Usimov [2.4K]

Answer:

The answer is "0.0000190 and 2.7 J".

Explanation:

$\to P_4=\frac{e^{-\beta}(4+\frac{1}{2}) hev}{2vb}\\\\$

$=\frac{e^{-9(1.35)}}{0.278v}\\\\=\frac{e^{-12.5}}{0.278}\\\\=\frac{0.000005285}{0.278}\\\\=0.0000190$

Given:

$h=6.626 \times 10^{-34}\\\\c=3\times 10^{10}\\\\v=558\ cm^{-1}\\\\K=1.38 \times 10^{-23}\\\\ T=298\\\\$

$E=\frac{hcv}{KT}\\\\$

by putting the value into the above formula so, the value is 2.7 J

6 0

3 years ago

What do you think would happen to a rock after billion years?

ANEK [815]

Answer:

Explanation:

It probably would have been broken down to smaller pieces and spread out around the world. Hope this help! :)

3 0

3 years ago