All categories

3 years ago

How can you determine an object mechanical energy

2 answers:

7 0

Objects have mechanical energyif they are in motion and/or if they are at some position relative to a zero potential energy position (for example, a brick held at a vertical position above the ground or zero height position). A moving car possesses mechanical energydue to its motion (kineticenergy).

AlexFokin [52]3 years ago

7 0

Kinetic energy + potential energy
KE=1/2mv^2
PE=M*G*H

You might be interested in

How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? given the reaction: 2na + cl2 → 2nacl?

Bess [88]

2Na + Cl2 → 2NaCl
46 g. ➡️ 117 g
x. ➡️ 29.3 g
$x = \frac{46 \times 29.3}{117} \\ x = 11.5 \: g$

5 0

3 years ago

Read 2 more answers

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0

2 years ago

explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th

Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

Rate of unknown gas (R₁) = R
Rate of CH₄ (R₂) = 3.4R
Molar mass of CH₄ (M₂) = 16 g/mol
Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

3 0

2 years ago

How does size influence the appearance of a star? Give an example in your response

Maurinko [17]

Makes it seem bigger and brighter

7 0

3 years ago

Read 2 more answers

What is the biome of danmarkshavn of Greenland?

earnstyle [38]

A picture. hope this helps at least a little.

3 0

2 years ago