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Marianna [84]
2 years ago
9

When a catalyst is added to a reversible reaction in equilibrium state the value of equilibrium constant

Chemistry
1 answer:
Sergio [31]2 years ago
6 0

Explanation:

The value of equilibrium constant doesn't change when a catalyst is added.

Equilibrium constant depends on Concentration of reactants , Pressure and Temperature.

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Are the fragments all the same size or shape
WINSTONCH [101]
Hey there! I believe this statement is False. No two fragments are exactly the same size, and all fragments vary on the density of the material, the speed at which it broke off of the material, and the amount of it that hit the ground. Because of this, some people may say "Oh, this is the same size as this," but in reality, nothing is exactly the same size. At least, on a molecular level. So the statement above is false.

Hope this helped!

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~Steve
7 0
3 years ago
Under which conditions does a sample of the same mass of carbon dioxide have the lowest
hjlf
The answer is B, as a solid and a low temperature would result in the lowest entropy value
8 0
3 years ago
One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HC
Leviafan [203]

Answer:

a. 92.4%

Explanation:

Based on the reaction:

2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)

To obtain the percent yield you need to obtain moles of trona and calculate thoeretical moles of Na₂CO₃, and the ratio of obtained moles / theoretical moles of Na₂CO₃ give percent yield, thus:

Moles of trona:

1.00 metric ton × (1x10³kg / 1 metric ton) × ( 1000moles /226.03 kg) = <em>4424 moles</em>

The theoretical moles of Na₂CO₃ that produce 4424 moles of trona are (Based on the reaction, 2 moles of trona produce 3 moles of Na₂CO₃):

4424 moles trona × (3 moles Na₂CO₃ / 2 moles trona) = <em>6636 moles of Na₂CO₃.</em>

The obtained moles of Na₂CO₃:

0.650 metric ton × (1x10³kg / 1 metric ton) × (1000 moles / 105.99kg) = <em>6133 moles</em>

The ratio of obtained moles / theoretical moles gives:

6133 moles / 6636 moles = 0.924 = <em>92.4%</em>

I hope it helps!

8 0
3 years ago
Calculate the mass of H2OH2O produced by metabolism of 2.4 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11
otez555 [7]

Answer:

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

Explanation:

2C_{57}H_{110}O_6+163O_2\rightarrow 114CO_2+110H_2O

Mass of fat = 2.4 kg = 2.4 × 1000 g = 2400 g

1 kg = 1000 g

Molar mass of fat = M

M = 57 × 12 g/mol + 110 × 1 g/mol+ 6 × 16 g/mol = 890 g/mol[/tex]

Moles of fat = \frac{2400 g}{890 g/mol}=2.6966 mol

According to reaction , 2 moles of fat gives 110 moles of water. Then 2.6966 moles of fat will give  ;

\frac{110}{2}\times 2.6966 mol=148.31 mol of water

Mass of 148.31 moles of water ;

148.31 mol × 18 g/mol = 2,669.58 g

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

8 0
2 years ago
Choose all the answers that apply. Plasma is made of _____.
andreev551 [17]
<span>'Plasma itself is made up of 91.5% water. It acts as a solvent for important proteins, nutrients, electrolytes, gases, and other substances essential to life.'

Source: </span><span>https://study.com/academy/lesson/what-is-blood-plasma-function-components.html

Hope this helps! :)</span>
5 0
3 years ago
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