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Veseljchak [2.6K]
4 years ago
9

10. Calculate A ramp is

Physics
1 answer:
inna [77]4 years ago
5 0

Answer: 3.33

Explanation:

MA = De/Dr

MA = 5.0/1.5

MA= 3.33

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WHAT IS THE NET FORCE REQUIRED TO GIVE AN AUTOMBILE OF MASS 1600KG AN ACCELERATION OF 4.5M/S2?
Fed [463]

Answer:

The required net force has a magnitude of  7200 N

Explanation:

Use Newton's 2nd Law to obtain the answer:

F_{net}= m\,*\,a\\F_{net}=1600 \,*\,4.5 \,= 7200\,\,N

4 0
4 years ago
The Doppler effect is the change in
anzhelika [568]

Yes indeed, that is a true statement.  Truer words are seldom written, and I could not agree with you more.

In case you are asking a question, I can kind of see how this might be a question if there is a blank after "... the change in ..." that is to be filled with one or more new words.

If that is the situation, then the blank can be filled with "frequency or wavelength" .

8 0
3 years ago
Read 2 more answers
a Porsche 911 accelerates from rest to 27 metre per second due north in 5.8 seconds the mass of the car is 1400 kg what is the m
user100 [1]

Answer:

The average force has a magnitude 6524 N due north.

Explanation:

The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.

a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)

v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s

a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s

Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.

The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N

Since the acceleration is due north, the average force takes the direction of the acceleration.

So the direction of the average force is due north

The average force has a magnitude 6524 N due north.

7 0
3 years ago
A block of mass 2 kg is launched by compressing a spring of force constant 1200 N/m. The block slides on a frictionless surface,
SVEN [57.7K]

Answer:

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Explanation:

3 0
3 years ago
A small steel wire of diameter 1.0mm is connected to an oscillator and is under a tension of 5.7N . The frequency of the oscilla
kotegsom [21]

Answer:

The power output of the oscillator is 0.350 watt.

Explanation:

Given that,

Diameter = 1.0 mm

Tension = 5.7 N

Frequency = 57.0 Hz

Amplitude = 0.54 cm

We need to calculate the power output of the oscillator

Using formula of the power

P=\dfrac{1}{2}\times\mu\times\omega^2\times a^2\times v

Put the value into the formula

P=\dfrac{1}{2}\times A\times\rho\times\omega^2\times a^2\times\dfrac{\sqrt{T}}{\mu}

P=\dfrac{1}{2}\times3.14\times(0.0005)^2\times7850\times(2\times\pi\times57.0)^2\times(0.54\times10^{-2})^2\times\sqrt{\dfrac{5.7}{3.14\times(0.0005)^2\times7850}}

P=0.350\ Watt

Hence, The power output of the oscillator is 0.350 watt.

3 0
3 years ago
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