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Mars2501 [29]
3 years ago
6

A dance form geared towards maximizing burning calories, created around the ___________ culture.

Physics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

Explanation:brazilian

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What type of energy moves through wires
jarptica [38.1K]

Answer:

current electricity

Explanation:

have a nice day

8 0
3 years ago
Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl
kherson [118]

Answer:

0.04455 Hz

Explanation:

Parameters given:

Wavelength, λ = 6.5km = 6500m

Distance travelled by the wave, x = 8830km = 8830000m

Time taken, t = 8.47hours = 8.47 * 3600 = 30492 secs

First, we find the speed of the wave:

Speed, v = distance/time = x/t

v = 8830000/30492 = 289.58 m/s

Frequency, f, is given as velocity divided by wavelength:

f = v/λ

f = 289.58/6500

f = 0.04455 Hz

8 0
3 years ago
A child rides a bicycle from rest, reaching a velocity of 3.8 m/s [E] after 4.7 s. What is the acceleration of the bicycle?
Maurinko [17]

Answer:

0.81 m/s^2

Explanation:

A child rides a bicycle from rest

The child reaches a velocity of 3.8m/s

The time is 4.7 secs

Therefore the acceleration can be calculated as follows

v= u + at

3.8= 0 + a(4.7)

3.8= 0 + 4.7a

3.8-0= 4.7a

3.8= 4.7a

a= 3.8/4.7

= 0.81 m/s^2

Hence the acceleration is 0.81 m/s^2

8 0
3 years ago
PLEASE HELP AND HURRY
julsineya [31]
It would be D. Equal to zero
3 0
3 years ago
Heat is extracted from a certain quantity of steam at
vodomira [7]

Answer:v=2452.91 m/s

Explanation:

Given

initially steam is at 100^{\circ}C and converted to 0^{\circ} C ice

Let m be the mass of steam

latent heat of fusion and vaporization for water is

L_f=3.33\times 10^5 J/kg

L_v=2.26\times 10^6 J/kg

Heat required to convert steam in to water at 100^{\circ}C

Q_1=m\times L_v=m\cdot 2.26\times 10^6 J

Heat required to lower water temperature to 0^{\circ}C

Q_2=m\times c\times \Delta T

Q_2=m\times 4.184\times (100)

Q_2=4.184m\times 10^5 J

Heat required to convert 0^{\circ}C water to ice at 0^{\circ}C is

Q_3=m\times L_f

Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J

Q=Q_1+Q_2+Q_3

Q=(2.26+0.4184+0.33)m\times 10^6 J

Q=3.0084m\times 10^6 J

So this energy is equal to kinetic energy of  bullet of mass m moving with velocity v

Q=\frac{1}{2}mv^2

3.0084m\times 10^6=\frac{1}{2}mv^2

v^2=3.0084\times 2\times 10^6

v=2.452\times 10^3 m/s

v=2452.91 m/s  

5 0
4 years ago
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