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Arte-miy333 [17]
3 years ago
12

In a solar system far far away, the sun's intensity is 100 W/m2 for a planet located a distance R away. What is the sun's intens

ity for a planet located at a distance 5 R from the Sun
Physics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

The sun's intensity for a planet located at a distance 5 R from the Sun is 4 W/m²

Explanation:

The intensity of Sun located at a distance of R away is 100\ W/m^2.

We need to find the sun's intensity for a planet located at a distance 5 R from the Sun. Intensity is given by :

I\propto \dfrac{1}{r^2}

So,

\dfrac{I_1}{I_2}=(\dfrac{r_2}{r_1})^2

Here, I₁ = 100 W/m² and r₁ = R and r₂ = 5R

I_2=\dfrac{I_1r_1^2}{r_2^2}

I_2=\dfrac{100(R^2)}{(5R)^2}\\\\I_2=\dfrac{100}{25}\\\\I_2=4\ W/m^2

So, the sun's intensity for a planet located at a distance 5 R from the Sun is 4 W/m².

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A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at re
Temka [501]

Answer:

F=32.24N

Explanation:

From the question we are told that:

Height h= 2.75 m

Lengthl = 5.25 m

Mass m=45kg

Final speed v_f=6.81

Generally the equation for Potential Energy P.E is mathematically given by

P.E=mgh

Therefore

Initial potential energy

P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J

Generally the equation for Kinetic Energy K.E is mathematically given by

K.E=0.5mv^2

Therefore

Final kinetic energy

K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J

Generally the equation for Work_done is mathematically given by

W=P.E_1-K.E_2\\\\W=169.3

Therefore

F=\frac{W}{d}\\\\F=\frac{169.3}{5.25}

F=32.24N

8 0
3 years ago
Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels
True [87]

Answer:

No.

Explanation:

Given that Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels. Note that the speedometer in a car is calibrated based on the tire's diameter and on the distance the tire covers in each revolution. (a) Will the reading of the speedometer change ?

Considering the formula

V = wr

Where

V = linear speed

W = angular speed

r = radius of the wheel.

But W = 2πrf

Where the the 2 and pi are constant. The radius of the first wheel will be small but counter balance with the larger frequency.

While the radius of the second wheel may be large but it will be of a small frequency.

We can therefore conclude that the reading on the speedometer will not change. Because speedometer will read the linear speed V.

7 0
3 years ago
Which representation shows the relationship between resistance and the length of a wire?
dybincka [34]

Answer:

R∝L

Explanation:

7 0
3 years ago
What is the most likely outcome of increasing the number of slits per unit distance on a diffraction grating?1) lines become nar
Nina [5.8K]

It's important to know that diffraction gratings can be identified by the number of lines they have per centimeter. Often, more lines per centimeter is more useful because the images separation is greater when this happens. That is, the distance between lines increases.

<h2>Therefore, the answer is 2.</h2>
8 0
2 years ago
Pascal's Principle states that (a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished
nika2105 [10]

Answer:

a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished at every point in the fluid and on the walls of the container.

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area(A2) of the piston.

P=F/A

P1=P2

F1/ A1= F2/ A2

F2= F1* A2/ A1

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

In an incompressible liquid, the volume and amount of mass does not vary when pressure is applied.

5 0
3 years ago
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