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2 years ago

A block of metal of density 3000 kg/m3 is 2m high and stands on a square base of side 0.5 m. Calculate:

Physics

1 answer:

labwork [276]2 years ago

8 0

Answer:

1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,

5) P = 58800 Pa

Explanation:

1) The area of the base is square

A = L²

A = 0.5²

A = 0.25 m²

2) The block is a parallelepiped

V = A h

V = 0.25 2

V = 0.5 m³

3) Density is defined

rho = m / V

m = rho V

m = 3000 0.5

m = 1500 kg

4) The weight of a body is

W = mg

W = 1500 9.8

W = 14700 N

5) The pressure is

P = F / A

in this case the force is equal to the weight of the body

P = 14700 / 0.25

P = 58800 Pa

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Answer:

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2 years ago

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3 years ago

A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D

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Answer:

Explanation:

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