Answer:
Average acceleration on first part of the chunk is given as
Average acceleration on second part of the chunk is given as
Explanation:
By momentum conservation along x direction we will have
so we have
also by energy conservation
by solving above equation we will have
Average acceleration on first part of the chunk is given as
Average acceleration on second part of the chunk is given as
Answer:
The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is
Explanation:
Here we have
Initial temperature of air T₁ = 20 °C = 293.15 K
Final temperature of air T₁ = 120 °C = 393.15 K
Initial pressure P₁ = 1 atm = 101325 Pa
Final pressure P₂ = Required
Area = A
Therefore we have for the pressure cooker, the volume is constant that is does not change
By Chales law
P₁/T₁ = P₂/T₂
P₂ = T₂×P₁/T₁ = 393.15 K× (101325 Pa/293.15 K) = 135,889.22 Pa
∴ P₂ = 135.88922 KPa = 135.9 kPa
Where Force = we have
Force = .