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horrorfan [7]
3 years ago
5

Which of the following is not a source of light? * a) sun b) star c) mirror d)cfl

Physics
1 answer:
Vladimir [108]3 years ago
5 0

I think that would be c) mirror because mirrors reflects light and can't create it.

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
spin [16.1K]

Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

          \lambda_1  = 574.2 nm

at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

          \lambda_ 1 =  574.2 nm

           

6 0
4 years ago
The vine has a fixed end, so Tarzan's path is circular. So the vine must not only support Tarzan's weight (or some component of
Minchanka [31]

Answer: hello your question lacks some data attached below is the missing data

answer : T - mg = ma_{c}

Explanation:

Given that the vine has a fixed end and Tarzan's path is circular

At Tarzans lowest point the point can be expressed as shown below.

It can be expressed as : T - mg = ma_{c}

8 0
3 years ago
How much power is used by car when it applies 40,000 J of work over a 5.6 second interval
Tcecarenko [31]

Answer:

7142.86W

Explanation:

Given parameters:

Work done by brake  = 40000J

Time taken = 5.6s

Unknown:

Power used by car  = ?

Solution:

Power can be defined as the rate at which work is done. It is mathematically expressed as;

        Power = \frac{work done }{time taken}

Now input the variables;

           Power  = \frac{40000}{5.6}   = 7142.86W

8 0
3 years ago
A seismic wave is energy released as the result of rock movement along a fault.<br> T/F
Vladimir [108]

Answer:

TRUE

Explanation:

7 0
3 years ago
How far does a car travel as it accelerates from rest to 24 m/s in 6 seconds?
____ [38]

Answer:

\boxed{\sf Distance \ travelled = 72 \ m}

Given:

Initial velocity (u) = 0 m/s (Starts from rest)

Final velocity (v) = 24 m/s

Time taken (t) = 6 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{24 + 0}{2} ) \times 6 \\  \\  \sf \implies s =  \frac{24}{2}  \times 6 \\  \\  \sf \implies s = 12 \times 6 \\  \\  \sf \implies s = 72 \: m

\therefore

Distance travelled by car (s) = 72 m

7 0
4 years ago
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