I’m assuming what you’re asking here is how to *factor* this expression. For that, let’s rearrange the expression into a more familiar form:
-c^2-4c+21
From here, we’ll factor out a -1 so that we have:
-(c^2+4c-21)
Let’s focus on the quadratic expression inside the parentheses. To find our factors (c + x)(c + y), we’ll need to find two terms x and y that multiply together to make -21 and add together to make 4. It turns out that the numbers -3 and 7 work out perfectly for that purpose (-3 x 7 = -21 and 7 + (-3) = 4), so substituting them in for x and y, we have:
(c + (-3))(c + 7)
(c - 3)(c + 7)
And adding back on the negative from a few steps earlier:
-(c - 3)(c + 7)
The first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
Given:
where,
n = number of terms
First term, a1 = 2
Second term, a2
a2 = {(2 - 1)/ 4} - 2
= 1/4 - 2
= (1-8) / 4
= - 7/4
Third term, a3
= {(3-1) / 4} - 2
= 2/4 - 2
= 1/2 - 2
= (1-4) / 2
= -3/2
Therefore, the first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
Learn more about sequence:
brainly.com/question/6561461
Answer:
Well your answer is yes, and you shouldn't be calling yourself d u m b
Step-by-step explanation:
(By the way, I would love Brainliest! :)
See56.7 cause it is the correct one to the 20th
