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Chemistry

1 answer:

noname [10]2 years ago

8 0

Answer: FeO is called ferrous oxide while Fe2O3 is ferric oxide

Explanation:

Ferrous oxide, commonly known as iron(II) oxide contains iron that lost 2 elections in the oxidation process. So it is able to bond with other atoms that have an extra 2 electrons to share. Ferric oxide, is commonly known as iron(III) oxide

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How do chemical weathering and physical weathering affect each other?

Zinaida [17]

Both processes occur in place. No movement is involved in weathering. Chemical weathering involves a chemical change in at least some of the minerals within a rock. Mechanical weathering involves physically breaking rocks into fragments without changing the chemical make-up of the minerals within it.

7 0

3 years ago

Metals lose electrons under certain conditions to attain a noble gas electron configuration. How many electrons must be lost by

viva [34]

Answer:

2 electrons

E. neon

Explanation:

Metals lose electrons under certain conditions to attain a noble gas electron configuration. Magnesium has 12 electrons and its electron configuration is

1s² 2s² 2p6⁶ 3s²

When magnesium loses 2 electrons, it acquires the electron configuration of neon (10 electrons).

5 0

3 years ago

HELP. I DONT KNOW WHAT TO DO. Barium sulfate, BaSO4, is made by the following reaction.

Ghella [55]

Answer:

$\boxed{\text{66.95 g BaSO$_{4}$}}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 261.34 233.39

Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃

m/g: 75.00

1. Moles of Ba(NO₃)₂

$\text{Moles of Ba(NO$_{3})_{2}$} = \text{75.00 g} \times \dfrac{\text{1 mol}}{\text{261.34 g}} = \text{0.286 98 mol}$

2. Moles of BaSO₄

The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂

$\text{Moles of BaSO$_{4}$}= \text{0.286 98 mol Ba(NO$_{3})_{2}$ } \times \dfrac{\text{1 mol BaSO$_{4}$}}{\text{1 mol Ba(NO$_{3})_{2}$}} = \text{0.286 98 mol BaSO$_{4}$}$

3. Mass of BaSO₄

$\text{Mass of BaSO$_{4}$} = \text{0.286 98 mol BaSO$_{4}$} \times \dfrac{\text{233.39 g BaSO$_{4}$}}{\text{1 mol BaSO$_{4}$}} = \textbf{66.98 g BaSO$_{4}$}\\\\\text{The theoretical yield of barium sulfate is } \boxed{\textbf{66.98 g BaSO$_{4}$}}$