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Viktor [21]
3 years ago
14

Which organelles surround the cell?

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer:

the nucleus the largest organelle in eukaryotic cells is surrounded by the cells

GalinKa [24]3 years ago
5 0

Answer:

Cell Wall, Cell Membrane, Nucleus, Endoplasmic Reticulum (ER), and Ribosome.

Explanation:

Hopefully this helps :).

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NaOH  + H2SO4 =
mariarad [96]
2NaOH+H_2SO_4\Rightarrow\ Na_2SO_4+2H_2O\\
NaOH+HNO_3\Rightarrow\ NaNO_3+H_2O\\
Cu(OH)_2+2HCl\Rightarrow\ CuCl_2+2H_2O\\
Cu(OH)2+H_2SO_4\Rightarrow\ CuSO_4+2H_2O\\
Cu(OH)_2+2HNO_3\Rightarrow\ Cu(NO_3)_2+2H_2O
3 0
3 years ago
A metal melts at 450 degrees celsius. Is this property of the metal classified as chemical or physical?
Romashka-Z-Leto [24]
It's a physical property because it doesn't change the element of the metal.
does this make sense?
8 0
3 years ago
What is a redox reaction?
Alexandra [31]

Answer:

A reaction in which the oxidation state of one element increases and another decreases

Explanation:

Redox reaction means both oxidation and reduction take place in that reaction.

So when an element oxides its oxidation state increases and when an element reduces its oxidation state decrease.

8 0
2 years ago
Read 2 more answers
You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
kicyunya [14]

Answer:

3,78 mL of 12,0wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 10^{-7,2}

Thus, you need to add:

[H⁺] = 10^{-7,2} - 10^{-8} = <em>5,31x10⁻⁸ M</em>

The total volume of the pool is:

7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,00x10⁻² moles of H⁺ × \frac{1 H_{2}SO_{4} moles}{2H^+ mole} = <em>5,00x10⁻³ moles of H₂SO₄</em>

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × \frac{98,1g}{1mol} × \frac{100 gsolution}{12 g H_{2}SO_{4} } × \frac{1mL}{1,080 g} = <em>3,78 mL of 12,0wt% H₂SO₄</em>

<em></em>

I hope it helps!

5 0
3 years ago
After passing through pyruvate dehydrogenase and the citric acid cycle, one mole of pyruvate will result in the formation of ___
mamaluj [8]

Answer:

The answer to be filled in the respective blanks in question is

3 and 1

Explanation:

So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.

Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1

 

7 0
3 years ago
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