A ball going down a hill and a football getting thrown into the air
In picture one and picture three there is an even amount of both X and Y. But in picture two there is double the amount of X than there is Y which also would change the rate from being .10 to .20
I believe it’s a COMPOUND
Options are as follow,
A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
<span>D. KH</span>₂PO₃
Answer;
The correct option is Option-D (KH₂PO₃).
Explanation:
Oxidation number of Phosphorous is calculated as,
As the normal oxidation number of K is +1, H is +1 and O is -2 so,
KH₂PO₃ = 0
0 shows that the molecule is neutral. Now puttion values of all elemnts except P,
(+1) + (+1)₂ + P + (-2)₃ = 0
+1 + 2 + P - 6 = 0
+3 + P - 6 = 0
+3 + P = +6
P = +6 - 3
P = +3
