Answer:
Both reactions share a common intermediate and differ only in the leaving group
Explanation:
The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.
Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.
In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.
The dehydration of cyclopentanol is shown in the balanced equation below:
Cyclopentanol => cyclopentene + H2O
Therefore, the alkene produced from the dehydration of cyclopentanol is cyclopentene.
The OH group is removed from the compound resulting to an alkene, cyclopentene. <span />
Answer:
45.8 mL
Explanation:
If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.
P₁ = 3.1 atm P₂ = 10.5 atm
V₁ = 155 mL V₂ = ? mL
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values
480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155
45.8 = V₂ <----- Divide both sides by 10.5
Answer:
Q < Ksp
Explanation:
The general equilibrium of a constant product solubility, ksp, is:
AB ⇄ A⁺ + B⁻
<em>Where Ksp is defined as:</em>
Ksp = [A⁺] [B⁻]
When [A⁺] [B⁻] = Ksp, the solution is saturated or oversaturated because there are the maximum amount of ions that solution can dissolve.
When the solution is oversaturated, AB is produced.
Now, in a unsaturated solution, the [A⁺] [B⁻] is less than the maximum amount that can be dissolved. That means:
[A⁺] [B⁻] = Q < Ksp
Q is defined in the same way than Ksp, just in Q the system is not in equilibrium.
Right answer is:
<h3>Q < Ksp</h3>
