Answer:
Percentage of first isotope = 69.152 %
Percentage of second isotope = 30.848 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope:
Let % = x %
Mass = 62.9296 amu
For second isotope:
% = 100 - x % (Since, there are only two isotopes)
Mass = 64.9278 amu
Average mass = 63.546 amu
Thus,
Solving,
1.9982 x = 138.18
Thus,
<u>Percentage of first isotope = x = 69.152 %</u>
<u>Percentage of second isotope = 100 - x % = 30.848 %</u>
Answer:
2.016 g/mol
Explanation:
Avogadro number
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For H₂:
2.016 g of H₂ = one mole of hydrogen gas = 6.022 × 10²³ molecules of hydrogen
The theoretical yield is 0.0110 g H₂.
<em>Moles of H₂O</em> = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O
<em>Moles of H₂</em> = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂
<em>Theoretical yield</em> of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)
= 0.0110 g H₂
