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2 years ago

25 Points:PLEASE HELP ASAP

Mathematics

1 answer:

alekssr [168]2 years ago

8 0

Answer:

I am sorry, what is your question? What do you <em>have </em>a question on?

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Y²÷2y²-12y+16÷2+y-2

Fynjy0 [20]

Y^2 / 4y-16 if you need the solving steps let me know

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3 years ago

Please help me solve this proof!!!!!

jolli1 [7]

statements:

1.) E is midpoint of TP

2) TP bisects MR

reasons:

1.)given

2) MT is congruent to PR (I think)

I might be wrong though so dont count on it being right. I hope I helped. ime not that good at math. I m not BAD but yea

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3 years ago

Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos

Marizza181 [45]

Given:

$\text{ Dimension = 3}\times5$

Sol:

Area of picture is:

$\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}$

If the cost $10 per square inch then price of 15 square inch is:

$\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}$

If the quadruple of dimension that mean:

$\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}$

So area is:

$\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}$

So price is:

$\begin{gathered} =60\times10 \\ \\ =600 \end{gathered}$

3 0

1 year ago

Which expression is equivalent to (2g^3+4)^2

babunello [35]

(2g^3+4)^2= 4g^6 + 16g^3 + 16
The answer is B.

7 0

3 years ago

Read 2 more answers

Find the shaded area. 4in 15in 19in 7in

worty [1.4K]

4*15=60
19*7=133
133-60=73
the shaded area is 73
:}

8 0

3 years ago