Question

Question 8 (5 points)

Answer 1

Answer:

d . The volume of the solvent used was less than 5 liters.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the stock (initial) solution by using the following equation:

$M_1V_1=M_2V_2$

Thus, we solve for, V1, which stands for the aforementioned volume of stock solution:

$V_1=\frac{M_2V_2}{M_1}$

Then, we plug in to obtain:

$V_1=\frac{5L*1M}{10M}\\\\V_1=0.5L$

Now, since the final volume was 5 L, we can infer that the volume of solvent is 4.5 L and that of the stock solution 0.5 L for a total of 5 L of diluted solution; therefore, the correct reasoning is d . The volume of the solvent used was less than 5 liters.

Regards!