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Bumek [7]
2 years ago
7

Suppose the data formed a line with a steeper slope. For the same change in temperature, how would the change in volume compare?

Chemistry
1 answer:
bogdanovich [222]2 years ago
4 0
Substances can change state, usually when they are heated or cooled. For example, liquid water turns into steam when it is heated enough, and it turns into ice when it is cooled enough. ... The closeness, arrangement and motion of the particles in a substance change when it changes state.
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How many Atoms are in H2COCH? Need asap pleassseee!
bearhunter [10]
There is a total of 12, wish you luckkkkkkkk
3 0
2 years ago
What is the condition of water in the hydrosphere right now?
SCORPION-xisa [38]

Answer:

           A planet's <u>hydrosphere</u> can be<u> liquid</u>, <u>vapor</u>, or <u>ice</u>. On Earth, in the places at the <u>north and south pole</u>, water exists in ice or glacier form, in the <u>atmosphere</u> it exists in vapor form and liquid water exists on the <u>surface</u> in the form of oceans, lakes and rivers. It also exists below ground as <u>groundwater</u>, in wells and aquifers. Water collects in clouds, then falls to Earth in the form of <u>rain or snow</u>,

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6 0
3 years ago
In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore
vitfil [10]

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

<span>% mass = 7.20 x 10^-3 %</span>

8 0
3 years ago
Read 2 more answers
a) A table tennis ball has been hit is about 13.16 times as fast as the speed for the swimming. What is the speed of the table t
Alex

x=swimming

The answer is X*13.16

7 0
3 years ago
Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublimes according to the following equation: CO2(s)→C
GREYUIT [131]

Answer:

m=8.79kg

Explanation:

First of all we need to calculate the heat that the water in the cooler is able to release:

Q=\rho * V*Cp*\Delta T

Where:

  • Cp is the mass heat capacity of water
  • V is the volume
  • \rho is the density

Q=1 g/cm^3 *15000 cm^3*4.184 \frac{J}{g*^{\circ}C}*(10-90)^{\circ}C

Q=-5020800 J=-5020.8 kJ

To calculate the mass of CO2 that sublimes:

-Q=\Delta H_{sub}*m

Knowing that the enthalpy of sublimation for the CO2 is: \Delta H_{sub}=571 kJ/kg

5020.8 kJ=571 kJ/kg*m

m=\frac{5020.8 kJ}{571 kJ/kg}=8.79kg

6 0
2 years ago
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