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2 years ago

A child in a boat throws a 6-kg package horizontally to the right with a speed of 8 m/s.

Physics

1 answer:

victus00 [196]2 years ago

4 0

Answer:

0.5 m/s

Explanation:

Using conservation of momentum, P1=P2, the system starts off with zero momentum as nothing is moving. But in the second part of the equation(P2) the child throws the package to the right. By Newton's third law, the child and the boat should move to the left. Plugging in what we know, 0= -90v + 6kg*8m/s. Solving for v you will get 0.5 meters per second. The mass is 90kg as that the is mass of the child and boat combined. I also made it negative as the boat and child move left (I designated this as the negative direction) and the package's momentum is positive as it is moving to the right.

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3 years ago

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3 years ago

A potential difference of 3.00 nV is set up across a 2.00 cm length of copper wire that has a radius of 2.00 mm. How much charge

Anvisha [2.4K]

The number of charge drifts are 3.35 X 10⁻⁷C

<u>Explanation:</u>

Given:

Potential difference, V = 3 nV = 3 X 10⁻⁹m

Length of wire, L = 2 cm = 0.02 m

Radius of the wire, r = 2 mm = 2 X 10⁻³m

Cross section, 3 ms

charge drifts, q = ?

We know,

the charge drifts through the copper wire is given by

q = iΔt

where Δt = 3 X 10⁻³s

and i = $\frac{V}{R}$

where R is the resistance

R = $\frac{pL}{r^{2} \pi }$

ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm

So, i = $\frac{\pi(r)^{2}V }{pL}$

q = $\frac{\pi(r^{2} )Vt }{pL}$

Substituting the values,

q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02

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