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Goshia [24]
3 years ago
11

A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th

e same as that of the water. Suppose that with its air sacs collapsed, a fish has a density of 1.05 g/cm3. To what fraction of its expanded body volume must the fish inflate the air sacs to reduce its density to that of water?
Physics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

V’/V= 1.05  

Explanation:

The density is defined with the ratio of the mass to the volume, for the fish with the collapsed sack

         ρ₁ = m / V

The density of the fish with the bag full of air is

         ρ₂ = m / V’

For the fish to float if it exerts its density must be exactly equal to that of the surrounding water

We clear the mass  and match

          m = ρ1 V = ρ2 V'        

          ρ₁ V = ρ₂ V’

         V ’/ V = ​​ρ₁ / ρ₂

         V ’/ V = ​​1.05 / 1

        V ’= 1.05 V

This is that the fish should increase its volume by 5%

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