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Goshia [24]
3 years ago
11

A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th

e same as that of the water. Suppose that with its air sacs collapsed, a fish has a density of 1.05 g/cm3. To what fraction of its expanded body volume must the fish inflate the air sacs to reduce its density to that of water?
Physics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

V’/V= 1.05  

Explanation:

The density is defined with the ratio of the mass to the volume, for the fish with the collapsed sack

         ρ₁ = m / V

The density of the fish with the bag full of air is

         ρ₂ = m / V’

For the fish to float if it exerts its density must be exactly equal to that of the surrounding water

We clear the mass  and match

          m = ρ1 V = ρ2 V'        

          ρ₁ V = ρ₂ V’

         V ’/ V = ​​ρ₁ / ρ₂

         V ’/ V = ​​1.05 / 1

        V ’= 1.05 V

This is that the fish should increase its volume by 5%

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Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>

<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F  equal to:

F=qE

In our problem we have q=-2.5 nC=-2.5\cdot 10^{-9} C and F=18 nN = 18 \cdot 10^{-9} N, so we can find the magnitude of the electric field:

E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m

The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.

B) The proton charge is equal to

e=1.6\cdot 10^{-19} C

Therefore, the magnitude of the force acting on the proton will be

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And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

7 0
3 years ago
How much energy is needed to melt 5 g of ice? The specific latent heat of melting for water is 334000 J/kg.
Katen [24]

Answer:

The needed energy to melt of ice is 1670 J.

Explanation:

Given that,

Mass of ice = 5 g

Specific latent heat = 334000 J/kg

We need to calculate the energy

Using formula of energy

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Where, m = mass

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Put the value into the formula

Q=5\times10^{-3}\times334000

Q=1670\ J

Hence, The needed energy to melt of ice is 1670 J.

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OlgaM077 [116]
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High voltage power is often carried in wire bundles made up of individual strands. In your initial post to the discussion, discu
Firdavs [7]

Answer:

<em>There will  be a huge problem of holding the wire strands together, and the power losses will also be amplified.</em>

Explanation:

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