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solong [7]
3 years ago
13

Using Hooke's law F spring = k dela x, find elastic constant of a spring that stretches 2cm when a 4 newton force is applied to

it
Answers in the picture

Physics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer: <em>2 N/cm  (B)</em>

Given that:

Spring stretches = 2 cm ,

Force  = 4 N,

<em>determine </em>

            the spring constant/elastic constant ( k)= ?

            We know that from hook's law, <em>F = k.x</em>  N

                                                                 4 = k × 2

                                                                => k  =4/2

                                                                         = 2 N/cm

The elastic constant is 2 N/cm

           

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Taking into account the Universal Law of Gravitation, the force of attraction between the tow objects is 8 N.

<h3>Universal Law of Gravitation</h3>

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

F=G\frac{Mm}{d^{2} }

where:

  • G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ \frac{Nm^{2} }{kg^{2} }.
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  • d is the distance that separates them.

<h3>Force of attraction in this case</h3>

In this case, two objects attract each other with a gravitational force of 32 newtons. The distance between the two objects is doubled.

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Then, if the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (d²= 2²= 4). The new force is then \frac{1}{4} of the original:

F=\frac{1}{4}×Foriginal

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<u><em>F= 8 N</em></u>

Finally, the force of attraction between the tow objects is 8 N.

Learn more about the Universal Law of Gravitation:

brainly.com/question/15967105

brainly.com/question/11359658

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6 0
2 years ago
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svet-max [94.6K]
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3 years ago
A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how
Nata [24]

Answer:

C. 72

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In a ideal transformer,

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Where Vp = primary voltage, Vs = secondary voltage, Ns = Secondary turn, Np = primary turn.

Making Ns the subject of the equation,

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pshichka [43]

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Therefore all the answer is False.

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