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3 years ago

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Using Hooke's law F spring = k dela x, find elastic constant of a spring that stretches 2cm when a 4 newton force is applied to

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1 answer:

photoshop1234 [79]3 years ago

6 0

Answer: <em>2 N/cm (B)</em>

Given that:

Spring stretches = 2 cm ,

Force = 4 N,

<em>determine </em>

the spring constant/elastic constant ( k)= ?

We know that from hook's law, <em>F = k.x</em> N

4 = k × 2

=> k =4/2

= 2 N/cm

The elastic constant is 2 N/cm

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$Bi = \frac{800 * 2.75 *10^{-2}}{0.607}$

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The time required for the egg to be cooked is mathematically represented as

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