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solong [7]
3 years ago
13

Using Hooke's law F spring = k dela x, find elastic constant of a spring that stretches 2cm when a 4 newton force is applied to

it
Answers in the picture

Physics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer: <em>2 N/cm  (B)</em>

Given that:

Spring stretches = 2 cm ,

Force  = 4 N,

<em>determine </em>

            the spring constant/elastic constant ( k)= ?

            We know that from hook's law, <em>F = k.x</em>  N

                                                                 4 = k × 2

                                                                => k  =4/2

                                                                         = 2 N/cm

The elastic constant is 2 N/cm

           

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