Question

What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump?
COP =

Answer 1

Complete Question

A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.

What is the refrigerator's coefficient of performance? COP

(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP

Answer:

a

 $COP = 8.49$

b

  $COP_1 = 9.49$  

Explanation:

From the question we are told that

     The lower operation temperature of refrigerator is  $T_1 = -8.00^oC = 265 \ K$

     The upper operation temperature of the refrigerator is   $T_2 = 23.2 ^oC = 296.2 \ K$

Generally the refrigerators coefficient of performance is mathematically represented as

        $COP = \frac{T_1}{T_2 - T_1 }$

=>     $COP = \frac{265}{296.2 - 265 }$

=>     $COP = 8.49$

Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as

            $COP_1 = \frac{T_2}{ T_2 - T_1}$  

=>         $COP_1 = \frac{296.2}{ 296.2 - 265 }$  

=>         $COP_1 = 9.49$