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notka56 [123]
3 years ago
9

Two narrow slits are 0.12 mm apart. light of wavelength 550 nm illuminates the slits, causing an interference pattern on a scree

n 1.0 m away. Light from each slit travels to the m=1 maximum on the right side of the central maximum. how much farther did the light from the left slit travel that the light from the right slit?
Physics
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

500 nm

Explanation:

d_l = Distance traveled by light from left slit

d_r = Distance traveled by light from right slit

\Delta x = Path difference = d_l-d_r

m = Order = 1

\lambda = Wavelength = 550 nm

Path difference is given by

\Delta x=m\lambda\\\Rightarrow d_l-d_r=1\times 550\\\Rightarrow d_l-d_r=500\ nm

The required distance is 500 nm

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3 years ago
An engine flywheel initially rotates counterclockwise at 6.77 rotations/s. Then, during 23.9 s, its rotation rate changes to 3.5
olganol [36]

Answer:

-2.70 rad/s²

Explanation:

Given that

ω1 = initial angular velocity of the flywheel, which is 6.77 rev/s

If we convert it to rad/s, we have

(6.77 x 2π) rad/s = 13.54π rad/s

ω2 = final angular velocity of the flywheel = -3.51 rev/s,

On converting to rad/s also, we have

(-3.51 x 2π) rad/s = 7.02π rad/s

α = average angular acceleration of the flywheel = ?

Δt = elapsed time = 23.9 s

Now, using the formula, α = (ω2 - ω1)/Δt. On substituting, we have

α = (-7.02π rad/s - 13.54π rad/s)/23.9 s

α = -20.56π rad/s / 23.9 s

α = -64.59 rad/s / 23.9 s

α = -2.70 rad/s²

Therefore, the average angular acceleration of the flywheel is -2.70 rad/s²

7 0
3 years ago
Why can't we implement the center tapped full wave rectifier without center-tapped transformer
maksim [4K]
For a full wave bridge you don't want a center tap
6 0
3 years ago
PLEASE HELP ASAP!!! NO LINKS! Which type of wave does the illustration depict?
Xelga [282]

Answer:

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Explanation:

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3 0
2 years ago
A purse at radius 2.10 m and a wallet at radius 3.15 m travel in uniform circular motion on the floor of a merry-go-round as the
vlada-n [284]

Complete question is:

A purse at radius 2.10 m and a wallet at radius 3.15 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the purse is 1.7 m/s^2 \hat i+3.20m/s^2 \hat j . At that instant and in unit-vector notation, what is the acceleration of the wallet?

Answer:

a'= 2.55 m/s^2\hat i + 4.8 m/s^2 \hat j    

Explanation:

Given: Purse is at radius, R=2.10 m

Wallet is at radius, R'=3.15 m

acceleration of the purse, a = 1.7 m/s^2 \hat i+3.20m/s^2 \hat j

a=r\omega^2

Both the purse and wallet would have same angular velocity \omega.

\sqrt \frac{a}{R}=\sqrt \frac{a'}{R'}

a'=\frac{a}{R}\times R \\ \Rightarrow a' = \frac{1.7 m/s^2 \hat i+3.20m/s^2 \hat j}{2.10 m}\times 3.15 m \\ a'= 2.55 m/s^2\hat i + 4.8 m/s^2 \hat j

5 0
3 years ago
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