If the object weighs 60N on Earth, then its mass is 6.12 kilograms.
If it weighs 60N on the moon, then its mass is 36.97 kilograms.
Whatever its mass is in one place, it has the same mass in any other place. Mass doesn't depend on location, but weight does.
Answer:
The magnification is 
Explanation:
From the question we are told that
The object distance is 
The focal length is 
From the lens equation we have that

=> 
substituting values


=> 
=> 
The magnification is mathematically represented as

substituting values


Average speed of the runner is the rate at which the runner covers the total distance. Average speed of the runner in the race is given by,
Average speed = 
Where
Total distance = Distance covered by the runner from initial to final position
Total time = time taken by the runner to cover entire distance
Instantaneous speed is the speed of the runner at the particular moment in the given time. Instantaneous speed is given by,
Instantaneous speed = 
x = position of the runner at time t
t = time taken to cover distance x
Hence, Average speed and instantaneous speed are different for a runner running in the race.