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Oksanka [162]
3 years ago
10

Photons with shorter wavelengths have larger

Physics
1 answer:
Zarrin [17]3 years ago
7 0

i think photons with shorter wavelengths have larger speed.

I apologise if its incorrect.

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Write the function of alcohol in a alcohol thermometer.​
Serhud [2]

Answer:

Ethanol-filled thermometers are used in preference to mercury for meteorological measurements of minimum temperatures and can be used down to −70 °C (−94 °F). The physical limitation of the ability of a thermometer to measure low temperature is the freezing point of the liquid used.

8 0
2 years ago
What is the wavelength of an fm radio signal that has a frequency of 91.7 mhz?
Digiron [165]

Answer:

The wavelength of the radio wave will be 3.271 m

Explanation:

We have given frequency of the radio signal f=91.7MhZ=91.7\times 10^6Hz

Speed of the light c=3\times 10^8m/sec

We have to find the wavelength of the radio signal

We know that wavelength is given by \lambda =\frac{c}{f}=\frac{3\times 10^8}{91.7\times 10^6}=3.271m

So the wavelength of the radio wave will be 3.271 m

3 0
3 years ago
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Kryger [21]

Answer:

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Explanation:

8 0
3 years ago
Aang and Appa are flying over Ba Sing Se. They covered 500 m in 30 seconds while heading east. What was their velocity?
barxatty [35]

Answer:

Explanation:

I need help to marysol;)

8 0
4 years ago
An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and
Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0
4 years ago
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