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Oksanka [162]
2 years ago
10

Photons with shorter wavelengths have larger

Physics
1 answer:
Zarrin [17]2 years ago
7 0

i think photons with shorter wavelengths have larger speed.

I apologise if its incorrect.

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Match the letters to the numbers for 30 points!
liq [111]

-- 'Ca' (Calcium) is an element.
-- The proton has a positive charge.
-- Nuclear fusion results in the synthesis of atoms of new elements.
-- H₂O (water) is a chemical compound.
-- Nuclear fission is a decay of the nucleus.
-- The atomic number of an element is the number of protons
      in each atom of it.
-- I suppose you're using the Greek letter  <span>η  ('eta', not 'nu')
      to represent the neutron.
-- I suppose you're using ' e ' to represent the electron.
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7 0
3 years ago
Read 2 more answers
Please answer D in the image with an explanation
puteri [66]

Answer:

The force is 274 N.

Explanation:

In figure 2:

(d) Let the tension in the string is T.

According to the Newton's second law,

Net force = mass x acceleration

Apply for 200N.

T - 200 sin 35 =\frac{200}{9.8}\times a \\T - 114.7 = 20.4 a..... (1)\\220 - T = \frac{220}{9.8}\times a\\220 - T = 22.45 a..... (2)\\Adding both the equations\\334.7 = 42.85 aa =7.81 m/s^{2}

Now put in (1)

T - 114.7 = 20.4 x 7.81

T = 274 N

4 0
2 years ago
Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 myf=5.00 m above the ground.
tensa zangetsu [6.8K]

Answer:

h' = 55.3 m

Explanation:

First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:

s = vt

where,

s = horizontal distance between arrow and orange = 60 m

v = initial horizontal speed of the arrow = v₀ Cos θ

θ = launch angle = 30°

v₀ = launch speed = 35 m/s

Therefore,

60 m = (35 m/s)Cos 30° t

t = 60 m/30.31 m/s

t = 1.98 s

Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:

h = Vi t + (1/2)gt²

where,

Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°

Vi = 17.5 m/s

Therefore,

h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²

h = 34.6 m + 19.2 m

h = 53.8 m

since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:

h' = h + y

h' = 53.8 m + 1.5 m

<u>h' = 55.3 m</u>

4 0
2 years ago
Astronomers believe that the universe began as an enclosed, cold object. true or false?
zhannawk [14.2K]
<span>Scientists believe that the earliest state of the universe was hot and dense. So I think this is false.</span>
4 0
3 years ago
Read 2 more answers
What would a plot of p versus 1/v look like for a fixed quantity of gas at a fixed temperature?
Romashka-Z-Leto [24]

Answer:

Straight Line

Explanation:

For an ideal gas,

PV = nRT

For a fixed quantity ( constant number of moles) of a gas at fixed temperature

Right side of the equation will be constant

Thus,

PV = C

So, P = \frac{C}{V} .

Thus P is directly related to \frac{1}{V}

That's why plot between P and  \frac{1}{V} will be an straight line.

7 0
3 years ago
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