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photoshop1234 [79]
3 years ago
8

I need help with this thanks!!!!!

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0
Is this supposed to be a matching game of some sort? If so, I don’t think any of these here match what’s in the tables.

Sorry :(
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Geri believed the answer to one of her homework problems was 2 cubed. After checking her work, she realized the correct answer w
Murrr4er [49]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
I don't get what I'm spose to put on it also how do you work this app I'm new
stiks02 [169]
I'm new too, but I'm pretty sure if you have a question then you ask it, attach a picture if needed, and people might see it and answer.
4 0
3 years ago
MEED HELP NOW 70 POINTS! Divide. 2/3÷4/5 28 815 56 88
Lelechka [254]

Hi,

Divide using Copy Dot Flop,

2/3 ÷ 4/5 = 2/3 x 5/4

Multiply,

2 x 5 = 10

3 x 4 = 12

= 10/12

Simplify,

10/12 = 5/6

Answer - 5/6

5 0
3 years ago
Read 2 more answers
In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen
Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type            ni                xi                  si

Graded       42           0.486            0.187

No-fines      42           0.359           0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}}  + \frac{s_{2}^{2} }{n_{2}} } }

Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42}  + \frac{0.02496 }{42} } }

Z = \frac{0.127 }{\sqrt{0.001468}}

Z = \frac{0.127 }{0.0377}

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0
3 years ago
Simplify the expression. 9r 3r2 – 5r 7
Ksenya-84 [330]
Your final answer is going to be 4r + 3r ^2 +7
7 0
3 years ago
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