If the sound of the quietest noise a person can hear is x, then the sound of the normal conversation is x(10^6). Also, the sound of the jet at takeoff is x(10^14). When we divide x(10^14) by x(10^6), we get the answer that is equal to 10^8. Thus, the sound of jet at takeoff is 10^8 times that of the normal conversation.
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It could be any time, but I would say 10. 10*10=100
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Answer:
11, 13, 15,
Step-by-step explanation:
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lol i answered ur last question also