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3 years ago

Does anybody know the formula needed to calculate distance given the values for mass, power, and time?

Physics

1 answer:

Hoochie [10]3 years ago

4 0

Answer:

Joules/second^2=(Newton×meter)/second^2.

Solving for mass: Kg= (second^3/ meter^2).

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A proton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. What is the magnitude and direc

Genrish500 [490]

Answer:

1. 5.12068 × 1011 N/C away from the proton

Explanation:

The electric field produced by a single point charge is given by:

$E=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

$q=1.6\cdot 10^{-19}C$ is the charge of the proton

$r=5.3\cdot 10^{-11} m$ is the distance at which we want to calculate the field

$k=8.99\cdot 10^9 Nm^2C^{-2}$ is the Coulomb's constant

Substituting into the formula,

$E=(8.99\cdot 10^9 Nm^2C^{-2})\frac{1.6\cdot 10^{-19}C}{(5.3\cdot 10^{-11}m)^2}=5.12068\cdot 10^{11} N/C$

And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is

1. 5.12068 × 1011 N/C away from the proton

4 0

4 years ago

A 40-N force acts on an 80-kg object, initially moving at 20 m/s. How far will the object travel in the next five seconds?

MakcuM [25]

Answer:

106.25 m

Explanation:

Acceleration a = force / mass

= 40 / 80 = 0.5 m /s²

initial velocity u = 20 m /s

a = 0.5 m /s²

time t = 5 s

displacement s = ?

s = ut + 1/2 a t²

= 20 x 5 + .5 x .5 x 5²

= 100 + 6.25

= 106.25 m .

6 0

3 years ago

A sound wave travels through air. In which regions of the wave are air molecules the least dense? *

mariarad [96]

Answer:

Rarefactions

Explanation:

3 0

3 years ago

Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens

Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

V has a dimension of [L/T]

x has a dimension of [L]

t has a dimension of [T]
from the equation, make z the subject of the relation
z = v/xt2 where 1/3 is treated as a constant
Substituting into the equation for z
z = L/T / L x T2
the dimension for z = 1/T3 i.e 1/ T - raised to power 3

5 0

3 years ago

If a compound has a very low melting and boiling point, it is likely that the compound possesses mainly which type of intermolec

sergejj [24]

For the given question above, I think there is an associated choice of answer for it. However, the answer for this is London Dispersion Forces. <span>Dipole-dipole forces and hydrogen bonding are much stronger, leading to higher melting and boiling points.</span>

6 0

4 years ago