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Fed [463]
3 years ago
5

Why, according to thoreau, are people better off being poor than wealthy?

Physics
1 answer:
goldenfox [79]3 years ago
7 0
<span>By being poor, you can become better because you can cultivate a better personality. Things, items, phones distract you & if you're poor, then you're more inclined to be productive & have more in a sense.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>
You might be interested in
A force did 80 j of work on an object in 4 m how big was the force
yanalaym [24]

Work = (force) x (distance)

80 J = (force) x (4 m)

Force = (80 J) / (4 m)  =  20 N

That's IF the force was in the same direction as the 4m of motion.
If the force was kind of slanted, then it had to be stronger, and
it had a component of 20N in the direction of the motion.

3 0
3 years ago
A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?
egoroff_w [7]
F = m*a, mass times acceleration.

F = 15*10 = 150 N
8 0
3 years ago
Read 2 more answers
Your bike gets a flat tire. Its mass is 10 kg and you are able to accelerate your bike .5 m/s/s. What is the force on the bike..
STALIN [3.7K]

Answer:

50N

Explanation:

Given parameters:

Mass of the bike   = 10kg

Acceleration  = 5m/s²  

Unknown:

Force on the bike  = ?

Solution:

To solve this problem, we apply Newton's second law of motion.

  Force  = mass x acceleration

 Force  = 10 x 5 = 50N

6 0
3 years ago
PLEASE HELP ASAP
77julia77 [94]

Answer:

<em>The first choice (32m/s) is the closest to the answer</em>

Explanation:

The magnitude of a vector is the distance between the initial and the end point of the vector.

Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

\mid \vec{V} \mid =\sqrt{V_x^2+V_y^2}

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.

Calculate the magnitude of the velocity:

\mid \vec{V} \mid =\sqrt{28^2+15^2}

\mid \vec{V} \mid =\sqrt{784+225}

\mid \vec{V} \mid =\sqrt{1009}

\mid \vec{V} \mid =31.8 \ m/s

The first choice (32m/s) is the closest to the answer

8 0
3 years ago
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