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mariarad [96]
2 years ago
11

For hundreds of years humans have been adding chemicals and other pollutants to the earths water supply. Can earths water ever b

e clean and pure again? What is clean and pure water?
Physics
1 answer:
AfilCa [17]2 years ago
7 0
Pure water is a colorless, odorless liquid with no molecules
except H₂O in it.  You can buy it at the supermarket, or make
it at home if you have the equipment and know how to use it.
At the supermarket, it's sold in gallon jugs, marked "Distilled
Water".

It turns out that pure water tastes bleah, and you would not
want to drink it for very long.

The Earth's water cycle is constantly purifying our water.
When the sun warms the ocean's surface and evaporates
water, what evaporates and rises into the atmosphere is
pure water.  The pollutants don't evaporate.  The clouds,
the rain, and the rivers are self-purifying.  Another example
of a process of nature that makes life possible here.

The junk is collecting in the oceans.  We're lucky that the oceans
have such huge volume that we haven't been able to significantly
pollute that entire layer of the Earth and kill off all sea life yet. 
But we're working on it.

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A baseball is hit with a bat. The direction of the ball is completely reversed and its speed is doubled. If the actual contact w
alexdok [17]
Before the impact, let the velocity of the baseball was v m/s.

After being hit by the bat its velocity is -2v
So, change in velocity, Deltav=v-(-2v)=3v
Acceleration is defined as the rate of change in velocity, i.e. actual change in velocity divided by the time taken to change it. Time taken to change velocity is the time of actual contact of the bat and ball, i.e. 0.31 s.

a=(Deltav)/(Deltat)
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8 0
3 years ago
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About how much time elapses between high tides on the same day?
Pani-rosa [81]
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3 years ago
On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnet
Otrada [13]

Answer:

1.907 x 10⁻⁵ J.

Explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

E = \mu V

E = (\dfrac{S}{c})\times V

where c is the speed of light.

E = (\dfrac{1.1\times 10^3}{3\times 10^8})\times 5.20

E = 1.907\times 10^{-5}\ J

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.

4 0
3 years ago
Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
Mandarinka [93]

Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 14.0 g

Molar mass = 137 g/mol

\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

7 0
2 years ago
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