Hi there!
Assuming the track is frictionless:
Cancel out the masses and rearrange to solve for velocity:
Plug in the given height and let g = 9.8 m/s²:
Someone please help me! Please help
1 answer:
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Answer:
<em>The second particle will move through the field with a radius greater that the radius of the first particle</em>
Explanation:
For a charged particle, the force on the particle is given as
also recall that work is force times the distance traveled
work = F x d
so, the work on the particle = F x d,
where the distance traveled by the particle in one revolution =
Work on a particle = 2πrF =
This work is proportional to the energy of the particle.
And the work is also proportional to the radius of travel of the particles.
Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.
Answer:
°C
Explanation:
= mass of the horseshoe = 0.35 kg
= mass of the water = 1.40 L = 1.40 kg
= mass of the iron pot = 0.45 kg
= specific heat of iron = 450 J kg⁻¹ °C⁻¹
= specific heat of water = 4186 J kg⁻¹ °C⁻¹
= initial temperature of the horseshoe = ?
= initial temperature of the water = 22 °C
= initial temperature of the iron pot = 22 °C
= final temperature = 32 °C
Using conservation of Heat
°C