Charlene records the number of pieces of red colored candies in ten bags of candy of assorted colors. find and interpret the mea
n absolute deviation of the data
6,6,7,7,8,8,10,10,11
6,6,7,7,8,8,10,10,11
1 answer:
To calculate the mean absolute deviation, you first must find the mean of the data and then find the difference between each piece of data and the mean.
Please see the attached picture for the work.
The mean absolute deviation is approximately 1.48.
This means that the numbers of candies in the 10 bags are all very close to one another. There is not much variation.
Please see the attached picture for the work.
The mean absolute deviation is approximately 1.48.
This means that the numbers of candies in the 10 bags are all very close to one another. There is not much variation.
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Answer:
a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
a)Less than 19.5 hours?
This is the pvalue of Z when X = 19.5. So
has a pvalue of 0.4013.
40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b)Between 20 hours and 22 hours?
This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So
X = 22
has a pvalue of 0.8413
X = 20
has a pvalue of 0.5
0.8413 - 0.5 = 0.3413
34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.