Hello,
Please, see the attached files.
Thanks.
Please, see the attached files.
Thanks.
Charlene records the number of pieces of red colored candies in ten bags of candy of assorted colors. find and interpret the mea
n absolute deviation of the data
6,6,7,7,8,8,10,10,11
6,6,7,7,8,8,10,10,11
1 answer:
To calculate the mean absolute deviation, you first must find the mean of the data and then find the difference between each piece of data and the mean.
Please see the attached picture for the work.
The mean absolute deviation is approximately 1.48.
This means that the numbers of candies in the 10 bags are all very close to one another. There is not much variation.
Please see the attached picture for the work.
The mean absolute deviation is approximately 1.48.
This means that the numbers of candies in the 10 bags are all very close to one another. There is not much variation.
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Answer:
a) the test statistic z = 1.891
the null hypothesis accepted at 95% level of significance
b) the critical values of 95% level of significance is zα =1.96
c) 95% of confidence intervals are (0.523 ,0.596)
Step-by-step explanation:
A survey of 700 adults from a certain region
Given sample sizes
Proportion of mean
<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device
p1 = p2
<u>Alternative hypothesis H1:</u>- p1 ≠ p2
a) The test statistic is
where
on calculation we get p = 0.56
now q =1-p = 1-0.56=0.44
after calculation we get z = 1.891
b) The critical value at 95% confidence interval zα = 1.96 (from z-table)
The calculated z- value < the tabulated value
therefore the null hypothesis accepted
<u>conclusion</u>:-
assume that there is no significant difference between males and women reported they buy clothing from their mobile device
p1 = p2
c) <u>95% confidence intervals</u>
The confidence intervals are P± 1.96(√PQ/n)
we know that =
after calculation we get P = 0.56 and Q =1-P =0.44
Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))
now substitute values , we get
( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))
on simplification we get (0.523 ,0.596)
Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals (0.523 ,0.596)</u>
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