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nikklg [1K]
1 year ago
8

Circulacion de electrones en un material conductor en determinado tiempo.

Chemistry
1 answer:
barxatty [35]1 year ago
4 0

Answer:

falso

Explanation:

tiempo no determinado El circulation de elctrones

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3h2(g)+n2(g)→2nh3(g)
melomori [17]

it would go to the Left

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3 years ago
Select all of the chirality centers in the structure. a selected atom will turn green.
scZoUnD [109]

Answer:

The answer is C is attached to four unique gatherings A, B C and D, Thus it frame two optical isomers as the perfect representations of one another.  

Explanation:

A critical class of isomers in which mixes have the equivalent sub-atomic recipe and structure, yet the distinction emerges from the introduction of the gatherings in the 3D space. Optical isomers are called as enantiomers.   Enantiomers are optical isomers whose identical representations are non-superimpose. They turn the plane enraptured light inverse way.   Optical action is characterized as the capacity of a choral atom to pivot the plane energized light. The enantiomers that pivots the plane energized light a clockwise way is called extraordinary, while the one that turns the plane spellbound light an anticlockwise way is called rotatory.  Basics  , Centrality is the major behind the optical movement of a natural atom.  Choral focus: A'C' particle in a particle turns into a choral focus when all the four valences of that molecule are fulfilled by synthetically unique gatherings.

4 0
3 years ago
We use Indicaters because
MatroZZZ [7]
<span>indicators are weak acids that exist as natural dyes and indicate the concentration of H+ (H3O+) ions in a solution via color change.</span>
8 0
3 years ago
Hydrogen iodide decomposes according to the equation: 2HI(g) H 2(g) + I 2(g), K c = 0.0156 at 400ºC A 0.660 mol sample of HI was
Ira Lisetskai [31]

Answer:

[HI] = 0.264M

Explanation:

Based on the equilibrium:

2HI(g) ⇄ H₂(g) + I₂(g)

It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:

<em>Kc = 0.0156 = [H₂] [I₂] / [HI]²</em>

<em />

As initial concentration of HI is 0.660mol / 2.00L = <em>0.330M, </em>the equlibrium concentrations will be:

[HI] = 0.330M - 2X

[H₂] = X

[I₂] = X

<em>Where X is reaction coefficient.</em>

<em />

Replacing in Kc:

0.0156 = [X] [X] / [0.330M - 2X]²

0.0156 = X² / [0.1089 - 1.32X + 4X² ]

0.00169884 - 0.020592 X + 0.0624 X² = X²

0.00169884 - 0.020592 X - 0.9376 X² = 0

Solving for X:

X = - 0.055 → False solution, there is no negative concentrations

X = 0.0330 → Right solution.

Replacing in HI formula:

[HI] = 0.330M - 2×0.033M

<h3>[HI] = 0.264M</h3>

7 0
3 years ago
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Arada [10]
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7 0
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