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mylen [45]
3 years ago
13

What is an example of a stable system

Chemistry
2 answers:
KiRa [710]3 years ago
8 0
An example of a stable system is a chemical reaction that is in equilibrium.A reaction at equilibrium has both forward and backward reactions in which the rate of forward reaction is equal to the rate of the backward reaction.
photoshop1234 [79]3 years ago
4 0
The answer would be a ball on a hill. hope that helped
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Do liquids have higher coefficients of expansion than solids do
zmey [24]

Answer: yes they do.

Explanation:

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4 0
3 years ago
Sodium chlorate = sodium chloride + oxygen formula
UNO [17]

Answer:

NaClO3 = NaCl + O2

Explanation:

Word equation: Sodium chlorate → Sodium chloride + Oxygen gas

6 0
2 years ago
How many miles of O2 can be produced by letting 12.00 miles of KC103 react?
Marat540 [252]
 2KClO3 --> 2KClO2 + O2 
    12                               6    (moles) 
The ratio of KClO3 and O2 is 2:1. This means 2 moles of KClO3 can create 1 mole of O2. So 12 moles of KClO3 will create 6 moles of O2. 
3 0
3 years ago
Viết các đồng phân cấu tạo mạch hở của C4H6O2 cùng nhóm chức axit
Aleksandr-060686 [28]

Answer:

+ axit

CH2=CH-CH2-COOH,

CH3-CH=CH-COOH (tính cả đồng phân hình học)

CH2=C(CH3)-COOH.

+ este

HCOOCH=CH-CH3 (tính cả đồng phân hình học)

HCOO-CH2-CH=CH2,

HCOOC(CH3)=CH2.

CH3COOCH=CH2

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8 0
3 years ago
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
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