Question

Commercial products commonly report concentration in terms of "percentage." Using this

Answer 1

The answer to the question is 0.8055 as the answer should not include units in it.

Molarity (M) = n/v

n = moles of solute

v = liters of solution

According to question

1% solution → 1 gram of solute for 100 milliliters of solution

2% solution → 2 grams of solute for 100 milliliters of solution

6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution

Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol

Atomic mass of Na = 22.98 g/mol

Atomic mass of Cl = 35.5 g/mol

Atomic mass of O = 16 g/mol

1 mol NaClO = 74.48 grams NaClO

74.48 grams NaClO = 1 mol NaClO

6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole

As unit molarity is mole / liter

So 100 milliliters = 0.1 liters

1 liter = 1000 milliliters

100 milliliters = 100/1000 liters = 0.1 liters

Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution

Molarity of NaClO = 0.08055 / 0.1 mole/L =  0.8055 mole/L

As in question it is mentioned that 'Do not type units into your answer'

So, Molarity of NaClO in clorox bleach = 0.8055

Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.

Learn more about Molarity here:

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