Answer:
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Answer:
Suppose you added some solid NaCl to a saturated solution of NaCl at 20℃ and warmed the mixture to 40℃. What would happen to the added NaCl?
Explanation:
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Answer: The volume for 0.850 mol of
from a
solution is 1700 mL.
The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Explanation:
Molarity is the number of moles of solute present in a liter of solution.
- As given moles of
are 0.850 mol and molarity of
solution is 0.5 M. Hence, its volume is calculated as follows.

Therefore, the volume for 0.850 mol of
from a
solution is 1700 mL.
- As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

So, volume for LiOH solution is calculated as follows.

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.