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Viktor [21]
3 years ago
8

The ball is dropped from a certain height and is falling to the ground. If its acceleration is a constant 9.8 meters per second

squared, how many seconds would it have dropped when the velocity is 49.0 m/s ????
A. 4.9 secs
B. 4 secs
C. 5 secs
D. 9.8 secs

Physics
1 answer:
lord [1]3 years ago
7 0
5 secs I did 49 divided by 9.8 and got 5
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Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
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