You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
F = G * M1M2/r^2
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
= 2.72x10^-5
</span><span>
Since,
1/2.72x10^-5 = 36800
The fraction ratio is 1/36800
</span>= <span>9.56x10^17 N</span>
Answer:
The turning points are those instants, moments or situations that happen in an absolutely unexpected way, as a result of which your life changes ... and nothing is the same as before.
The moment of inertia is ![24.8 kg m^2](https://tex.z-dn.net/?f=24.8%20kg%20m%5E2)
Explanation:
The total moment of inertia of the system is the sum of the moment of inertia of the rod + the moment of inertia of the two balls.
The moment of inertia of the rod about its centre is given by
![I_r = \frac{1}{12}ML^2](https://tex.z-dn.net/?f=I_r%20%3D%20%5Cfrac%7B1%7D%7B12%7DML%5E2)
where
M = 24 kg is the mass of the rod
L = 0.96 m is the length of the rod
Substituting,
![I_r = \frac{1}{12}(24)(0.96)^2=1.84 kg m^2](https://tex.z-dn.net/?f=I_r%20%3D%20%5Cfrac%7B1%7D%7B12%7D%2824%29%280.96%29%5E2%3D1.84%20kg%20m%5E2)
The moment of inertia of one ball is given by
![I_b = mr^2](https://tex.z-dn.net/?f=I_b%20%3D%20mr%5E2)
where
m = 50 kg is the mass of the ball
is the distance of each ball from the axis of rotation
So we have
![I_b = (50)(0.48)^2=11.5 kg m^2](https://tex.z-dn.net/?f=I_b%20%3D%20%2850%29%280.48%29%5E2%3D11.5%20kg%20m%5E2)
Therefore, the total moment of inertia of the system is
![I=I_r + 2I_b = 1.84+ 2(11.5)=24.8 kg m^2](https://tex.z-dn.net/?f=I%3DI_r%20%2B%202I_b%20%3D%201.84%2B%202%2811.5%29%3D24.8%20kg%20m%5E2)
Learn more about inertia:
brainly.com/question/2286502
brainly.com/question/691705
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(a) The object moves with uniform velocity from A to B.
(b) The object moves with constant velocity from B to C.
(c) The object moves with increasing velocity from C to D.
<h3>
Velocity of the object from point A to B</h3>
V(A to B) = (6 - 0)/(4 - 0) = 1.5 m/s
<h3>
Velocity of the object from point B to C</h3>
V(B to C) = (6 - 6)/(11 - 4) = 0 m/s
<h3>
Velocity of the object from point C to D</h3>
V(C to D) = (7 - 6)/(12 - 11) = 1 m/s
final velocity = 1 + 1.5 m/s = 2.5 m/s
Thus, we can conclude the following;
The object moves with uniform velocity from A to B.
The object moves with constant velocity from B to C.
The object moves with increasing velocity from C to D.
Learn more about velocity here: brainly.com/question/6504879
#SPJ1
Answer:
Explanation:
We shall apply law of conservation of momentum .
Momentum before collision = momentum after collision .
Momentum before collision = 400 kg m/s
Momentum after collision = 5 x v + 11 x 15
where v is velocity of A after the collision .
5 x v + 11 x 15 = 400
5 v = 400 - 165
5v = 235
v = 47 m /s .