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3 years ago

When cold milk

Physics

1 answer:

monitta3 years ago

7 0

Answer:

See explanation below.

Explanation:

The internal energy (kinetic energy) of the milk particles increases thus warming the milk up, while the internal energy of the coffee particles reduce their initial average speed as they are imparting energy to the slow milk particles.

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Suppose that there are N=108 two-state systems, each with energy difference E=6 × 10-21 J between the two states. The environmen

kati45 [8]

Answer:

The value of $\dfrac{dU}{dM}$ is $6\times10^{-29}\ J/unit$ .

Explanation:

Given that,

Number $N=10^{8}$

Energy difference = 6\times10^{-21}\ J[/tex]

Temperature T =300 K

We need to calculate the value of $\dfrac{dU}{dM}$

We know that,

$\dfrac{dU}{dM}=\dfrac{energy\ difference}{Change\ in\ number\ of\ system}$

$\dfrac{dU}{dM}=\dfrac{6\times10^{-21}}{10^{8}}$

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4 years ago

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

$x_2 = -2.3356$

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

$v = u + at$

=> $v = 0.060 + (-0.380 * 3.80)$

=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

=> $x_2 = -2.3356$

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3 years ago