First one, for instance they become conductors or insulators depending on the temperature!
Answer:
Explanation:
The rate of change in volume is proportional to the surface area:
dV/dt = kA
Integrating:
V = kAt + C
At t=0, V = s, so:
s = kA(0) + C
C = s
Therefore:
V = kAt + s
Hi!
The correct answer would be: the width of I-bands
The sacromere is the smallest contractile unit of striated muscles. These units comprise of filaments (fibrous proteins) that, upon muscle contraction or relaxation, slide past each other. The sacromere consists of thick filaments (myosin) and thin filaments (actin).
<em>Refer to the attached picture to clearly see the structure of a sacromere.</em>
<u>When a sacromere contracts, a series of changes take place which include:</u>
<em>- Shortening of I band, and consequently the H zone</em>
<em>- The A line remains unchanged</em>
<em>- Z lines come closer to each other (and this is due to the shortening of the I bands) </em>
The only changes that take place occur in the zones/areas in the sacromere (as mentioned), not in the filaments (actin and myosin) that make the up the sacromere; hence all other options are wrong.
Hope this helps!
Answer:
Approximately
(approximately
) assuming that the magnetic field and the wire are both horizontal.
Explanation:
Let
denote the angle between the wire and the magnetic field.
Let
denote the magnitude of the magnetic field.
Let
denote the length of the wire.
Let
denote the current in this wire.
The magnetic force on the wire would be:
.
Because of the
term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is
.)
In this question:
(or, equivalently,
radians, if the calculator is in radian mode.)
.
.
.
Rearrange the equation
to find an expression for
, the current in this wire.
.
Answer:
kE=0.0735 J
Explanation:
Given that
Radius ,R=10 cm = 0.1 m
Mass ,m= 3 kg
Angular speed ,ω = 3.5 rad/s
We know that moment of inertia for solid sphere given as

Kinetic energy

Now by putting the values


kE=0.0735 J
Therefore the kinetic energy will be 0.0735 J