Answer:
-- Volume of base used
--- Molarity of base
Explanation:
Given
-- Volume of acid used
--- Buret Initial reading
--- Buret Final reading
--- Molarity of the acid
Solving (a): Volume of base used (VB)
This is calculated by subtracting the initial reading from the final reading of the base buret.
i.e.
Solving (b): Molarity base (MB)
This is calculated using:
Make MB the subject
This gives:
Solving (c): <em>There is no such thing as average molarity</em>
Answer:
The candle ran out of oxygen
Explanation:
There is a concept known as the fire triangle, the three things present for a fire to start and burn. Heat, Oxygen, Fuel. Take any one of the three away and the fire goes out. Pour water on a fire, and it absorbs the heat, put a jar over it, it removes the oxygen, stop adding wood to a campfire it goes out.
Answer:
C⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
A divergent boundary is when two tectonic plates move apart from one another.
24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
Answer:
The Ka is 9.11 *10^-8
Explanation:
<u>Step 1: </u>Data given
Moles of HX = 0.365
Volume of the solution = 835.0 mL = 0.835 L
pH of the solution = 3.70
<u>Step 2:</u> Calculate molarity of HX
Molarity HX = moles HX / volume solution
Molarity HX = 0.365 mol / 0.835 L
Molarity HX = 0.437 M
<u />
<u>Step 3:</u> ICE-chart
[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4
Initial concentration of HX = 0.437 M
Initial concentration of X- and H3O+ = 0M
Since the mole ratio is 1:1; there will react x M
The concentration at the equilibrium is:
[HX] = (0.437 - x)M
[X-] = x M
[H3O+] = 1.995*10^-4 M
Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4
[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M
[X-] = x = 1.995*10^-4 M
<u>Step 4: </u>Calculate Ka
Ka = [X-]*[H3O+] / [HX]
Ka = ((1.995*10^-4)²)/ 0.437
Ka = 9.11 *10^-8
The Ka is 9.11 *10^-8
