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vagabundo [1.1K]
3 years ago
9

In completing a Fischer Esterification experiment using acetic acid and unknown alcohol catalyzed by sulfuric acid a student sta

rts with excess acetic acid with the intention of shifting the equilibrium towards formation of product. Identify the law used to predict this effect.
Chemistry
1 answer:
masha68 [24]3 years ago
3 0

Answer:

The equilibrium law

Explanation:

According to the equilibrium law , when $\text{concentration}$ of any of the  reactants or the products in the reaction at an equilibrium state,  is changed, then it changes the composition of equilibrium mixture in order to minimize the effect of

Acetic acid (in excess) + $\text{alcohol}$ ⇄  $\text{ester}$ + water

$\text{Fischer esterification}$ is a reaction which involves the equilibrium. So to force the reaction towards the side of $\text{ester}$, one of the reactant is taken in excess. All this can be explained easily by applying the equilibrium law.

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andrey2020 [161]
False. Electromagnetic and Gravitational forces can overcome .
8 0
3 years ago
Read 2 more answers
A
BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of SO_2 molecules in 9.87 moles of SO_2:

6.02214076 × 10^{23} x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

1.40 x 10^{22} ÷ 6.02214076 × 10^{23}

0.2324754694 x 10^{-1} moles.

0.23 x 10^{-1} moles.

D. The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O:

2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

6 0
1 year ago
Trace amounts of sulfur (S) in coal are burned in the presence of diatomic oxygen (O2) to form sulfur dioxide (SO2). Determine t
Mashcka [7]

Answer:

0.99 kg O₂

1.9 kg SO₂

Explanation:

Let's consider the reaction between sulfur and oxygen to form sulfur dioxide.

S + O₂ → SO₂

The mass ratio of S to O₂ is 32.07:32.00. The mass of oxygen required to react with 1 kg of sulfur is:

1 kg S × (32.00 kg O₂/32.07 kg S) = 0.998 kg O₂

The mass ratio of S to SO₂ is 32.07:64.07. The mass of sulfur dioxide formed when 1 kg of sulfur is burned is:

1 kg S × (64.07 kg SO₂/32.07 kg S) = 1.99 kg SO₂

3 0
3 years ago
A sample of gas has a volume of 3.75 L at a temperature of 25°C and a pressure of 1.15 atm. What will the volume be at a tempera
omeli [17]

Answer: V = 5.1 L

Explanation: To find the new volume, we will use the formula of Combined Gas Law and derive V2. We also need to convert first the temperature in Kelvin and convert torr to atm ( 1 atm = 760 torrs ).

Solution attached.

5 0
2 years ago
PLEASE HELP ME ASAP What is the volume of 28.9 g of mercury if the density is 13.8 g/mL? *
strojnjashka [21]

Answer:

2.09 mL

Explanation:

density = mass/volume

13.8 = 28.9/v

13.8v = 28.9

v = 2.09 mL

8 0
2 years ago
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